What is factor y^2+3y-28 ?

The solution to factor y^2+3y-28 is (y-4)(y+7)

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factor y^2+3y-28

factor

y^{2} + 3 y - 28

(y - 4) (y + 7)

Solution steps

y^{2} + 3 y - 28

Break the expression into groups

= (y^{2} - 4 y) + (7 y - 28)

Factor out

y

from

y^{2} - 4 y : y (y - 4)

Factor out

7

from

7 y - 28 : 7 (y - 4)

= y (y - 4) + 7 (y - 4)

Factor out common term

y - 4

= (y - 4) (y + 7)

x^{5} + x^{7}

3^{l o g_{3} (6) + l o g_{9} (16)}

(2 \cdot 4 - i) (\frac{4}{5} - 2 i)

(4 a b^{2} c)^{3}

\frac{y - x}{x ^{2} - y ^{2}}