What are the solutions to the equation -x^2+3x-21=0 ?

The solutions to the equation -x^2+3x-21=0 are x= 3/2-i(5sqrt(3))/2 ,x= 3/2+i(5sqrt(3))/2

Find the zeros of -x^2+3x-21=0

The zeros of -x^2+3x-21=0 are x= 3/2-i(5sqrt(3))/2 ,x= 3/2+i(5sqrt(3))/2

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- x^{2} + 3 x - 21 = 0

x = \frac{3}{2} - i \frac{5 3}{2}, x = \frac{3}{2} + i \frac{5 3}{2}

Solution steps

- x^{2} + 3 x - 21 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 1 ) ( - 21 )}{2 ( - 1 )}

Simplify

3^{2} - 4 (- 1) (- 21) : 53 i

x_{1, 2} = \frac{- 3 \pm 5 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 3 + 5 3 i}{2 ( - 1 )}, x_{2} = \frac{- 3 - 5 3 i}{2 ( - 1 )}

x = \frac{- 3 + 5 3 i}{2 ( - 1 )} : \frac{3}{2} - i \frac{5 3}{2}

x = \frac{- 3 - 5 3 i}{2 ( - 1 )} : \frac{3}{2} + i \frac{5 3}{2}

The solutions to the quadratic equation are:

x = \frac{3}{2} - i \frac{5 3}{2}, x = \frac{3}{2} + i \frac{5 3}{2}

s^{4} - 625

5 x y - 4 p y

3 x^{2} + 7 x - 6 \geq 0

\frac{\frac{1}{5} - \frac{5}{4}}{\frac{7}{2} - \frac{3}{4}}

16 g h + 24 g - 2 h - 3

What are the solutions to the equation -x^2+3x-21=0 ?
The solutions to the equation -x^2+3x-21=0 are x= 3/2-i(5sqrt(3))/2 ,x= 3/2+i(5sqrt(3))/2
Find the zeros of -x^2+3x-21=0
The zeros of -x^2+3x-21=0 are x= 3/2-i(5sqrt(3))/2 ,x= 3/2+i(5sqrt(3))/2