What are the solutions to the equation (b+12)^2=81 ?

The solutions to the equation (b+12)^2=81 are b=-3,b=-21

Find the zeros of (b+12)^2=81

The zeros of (b+12)^2=81 are b=-3,b=-21

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(b + 12)^{2} = 81

b = - 3, b = - 21

Solution steps

(b + 12)^{2} = 81

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

b + 12 = 81 : b = - 3

Solve

b + 12 = - 81 : b = - 21

The solutions to the quadratic equation are:

b = - 3, b = - 21

28 > 4 n

\frac{3 \cdot 180}{2}

\frac{x ^{15}}{x ^{10}}

\frac{1}{4} + \frac{1}{3}

1 + \frac{0.08}{12}

What are the solutions to the equation (b+12)^2=81 ?
The solutions to the equation (b+12)^2=81 are b=-3,b=-21
Find the zeros of (b+12)^2=81
The zeros of (b+12)^2=81 are b=-3,b=-21