What is ((3-2i))/((-1+i)) ?

The solution to ((3-2i))/((-1+i)) is -5/2-1/2 i

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simplify ((3-2i))/((-1+i))

simplify

\frac{( 3 - 2 i )}{( - 1 + i )}

- \frac{5}{2} - \frac{1}{2} i

Solution steps

\frac{3 - 2 i}{- 1 + i}

Multiply by the conjugate

\frac{- 1 - i}{- 1 - i}

= \frac{( 3 - 2 i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )}

Simplify

\frac{( 3 - 2 i ) ( - 1 - i )}{( - 1 + i ) ( - 1 - i )} : \frac{- 5 - i}{2}

= \frac{- 5 - i}{2}

Apply the fraction rule:

\frac{a + bi}{c} = \frac{a}{c} + \frac{b}{c} i

= \frac{- 5}{2} + \frac{- 1}{2} i

Simplify

\frac{- 5}{2} + \frac{- 1}{2} i : - \frac{5}{2} - \frac{1}{2} i

= - \frac{5}{2} - \frac{1}{2} i

2 \cdot 32

x^{3} y + x y^{3}

36 \frac{3}{2}

\frac{4}{26}

(2 z + 3)^{3}