What are the solutions to the equation 5u^2-3u+2=0 ?

The solutions to the equation 5u^2-3u+2=0 are u= 3/10+i(sqrt(31))/(10),u= 3/10-i(sqrt(31))/(10)

Find the zeros of 5u^2-3u+2=0

The zeros of 5u^2-3u+2=0 are u= 3/10+i(sqrt(31))/(10),u= 3/10-i(sqrt(31))/(10)

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5 u^{2} - 3 u + 2 = 0

u = \frac{3}{10} + i \frac{31}{10}, u = \frac{3}{10} - i \frac{31}{10}

Solution steps

5 u^{2} - 3 u + 2 = 0

Solve with the quadratic formula

u_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 5 \cdot 2}{2 \cdot 5}

Simplify

(- 3)^{2} - 4 \cdot 5 \cdot 2 : 31 i

u_{1, 2} = \frac{- ( - 3 ) \pm 31 i}{2 \cdot 5}

Separate the solutions

u_{1} = \frac{- ( - 3 ) + 31 i}{2 \cdot 5}, u_{2} = \frac{- ( - 3 ) - 31 i}{2 \cdot 5}

u = \frac{- ( - 3 ) + 31 i}{2 \cdot 5} : \frac{3}{10} + i \frac{31}{10}

u = \frac{- ( - 3 ) - 31 i}{2 \cdot 5} : \frac{3}{10} - i \frac{31}{10}

The solutions to the quadratic equation are:

u = \frac{3}{10} + i \frac{31}{10}, u = \frac{3}{10} - i \frac{31}{10}

\frac{2}{4} + \frac{3}{4}

5 x p + 5 x

∣ 10 - 4 x ∣ \leq 1

∣ x - 4 ∣ > 8

What are the solutions to the equation 5u^2-3u+2=0 ?
The solutions to the equation 5u^2-3u+2=0 are u= 3/10+i(sqrt(31))/(10),u= 3/10-i(sqrt(31))/(10)
Find the zeros of 5u^2-3u+2=0
The zeros of 5u^2-3u+2=0 are u= 3/10+i(sqrt(31))/(10),u= 3/10-i(sqrt(31))/(10)