What is expand (2a^4-y^5)^3 ?

The solution to expand (2a^4-y^5)^3 is 8a^{12}-12a^8y^5+6a^4y^{10}-y^{15}

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expand (2a^4-y^5)^3

expand

(2 a^{4} - y^{5})^{3}

8 a^{12} - 12 a^{8} y^{5} + 6 a^{4} y^{10} - y^{15}

Solution steps

(2 a^{4} - y^{5})^{3}

Apply Perfect Cube Formula:

(a - b)^{3} = a^{3} - 3 a^{2} b + 3 a b^{2} - b^{3}

(2 a^{4} - y^{5})^{3} = (2 a^{4})^{3} - 3 (2 a^{4})^{2} y^{5} + 3 \cdot 2 a^{4} (y^{5})^{2} - (y^{5})^{3}

= (2 a^{4})^{3} - 3 (2 a^{4})^{2} y^{5} + 3 \cdot 2 a^{4} (y^{5})^{2} - (y^{5})^{3}

Simplify

(2 a^{4})^{3} - 3 (2 a^{4})^{2} y^{5} + 3 \cdot 2 a^{4} (y^{5})^{2} - (y^{5})^{3} : 8 a^{12} - 12 a^{8} y^{5} + 6 a^{4} y^{10} - y^{15}

= 8 a^{12} - 12 a^{8} y^{5} + 6 a^{4} y^{10} - y^{15}

\frac{2}{3 2}

(0.5 x + 2 y)^{2}

\frac{2}{5} + (- \frac{6}{35})

sin (x) (x)

\frac{3 ( x + h ) ^{2} - 3 x ^{2}}{h}

What is expand (2a^4-y^5)^3 ?
The solution to expand (2a^4-y^5)^3 is 8a^{12}-12a^8y^5+6a^4y^{10}-y^{15}