What is ((x+3)^3-8)/(x+1) ?

The solution to ((x+3)^3-8)/(x+1) is x^2+8x+19

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simplify ((x+3)^3-8)/(x+1)

simplify

\frac{( x + 3 ) ^{3} - 8}{x + 1}

x^{2} + 8 x + 19

Solution steps

\frac{( x + 3 ) ^{3} - 8}{x + 1}

Expand

(x + 3)^{3} - 8 : x^{3} + 9 x^{2} + 27 x + 19

= \frac{x ^{3} + 9 x ^{2} + 27 x + 19}{x + 1}

Factor

x^{3} + 9 x^{2} + 27 x + 19 : (x + 1) (x^{2} + 8 x + 19)

= \frac{( x + 1 ) ( x ^{2} + 8 x + 19 )}{x + 1}

Cancel the common factor:

x + 1

= x^{2} + 8 x + 19

2 4^{4}

(2 a^{2} - a + 4)^{2}

\frac{15 x ^{2} - 234 x + 135}{15 - x}

\frac{8}{5} \cdot \frac{5}{8}

\frac{3}{y - 2} - \frac{2}{2 - y}