What is (3x^3+2x^2)/(x^2-x) ?

The solution to (3x^3+2x^2)/(x^2-x) is (x(3x+2))/(x-1)

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simplify (3x^3+2x^2)/(x^2-x)

simplify

\frac{3 x ^{3} + 2 x ^{2}}{x ^{2} - x}

\frac{x ( 3 x + 2 )}{x - 1}

Solution steps

\frac{3 x ^{3} + 2 x ^{2}}{x ^{2} - x}

Factor

3 x^{3} + 2 x^{2} : x^{2} (3 x + 2)

= \frac{x ^{2} ( 3 x + 2 )}{x ^{2} - x}

Factor

x^{2} - x : x (x - 1)

= \frac{x ^{2} ( 3 x + 2 )}{x ( x - 1 )}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

x^{2} = xx

= \frac{xx ( 3 x + 2 )}{x ( x - 1 )}

Cancel the common factor:

x

= \frac{x ( 3 x + 2 )}{x - 1}

(3 x^{2} - 7)^{2}

\frac{7 x ^{3}}{3}

14 x^{12} x^{9}

(v - 1) (3 v - 3)

(3 x)^{3}

What is (3x^3+2x^2)/(x^2-x) ?
The solution to (3x^3+2x^2)/(x^2-x) is (x(3x+2))/(x-1)