What is factor ((1/4 x^2+ax+(2a-8)-8))/(2(x+2)) ?

The solution to factor ((1/4 x^2+ax+(2a-8)-8))/(2(x+2)) is (x^2+4ax+8a-64)/(8(x+2))

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factor ((1/4 x^2+ax+(2a-8)-8))/(2(x+2))

factor

\frac{( \frac{1}{4} x ^{2} + a x + ( 2 a - 8 ) - 8 )}{2 ( x + 2 )}

\frac{x ^{2} + 4 a x + 8 a - 64}{8 ( x + 2 )}

Solution steps

\frac{\frac{1}{4} x ^{2} + a x + ( 2 a - 8 ) - 8}{2 ( x + 2 )}

Remove parentheses:

(a) = a

= \frac{\frac{1}{4} x ^{2} + a x + 2 a - 8 - 8}{2 ( x + 2 )}

Subtract the numbers:

- 8 - 8 = - 16

= \frac{\frac{1}{4} x ^{2} + a x + 2 a - 16}{2 ( x + 2 )}

\frac{1}{4} x^{2} = \frac{x ^{2}}{4}

= \frac{\frac{x ^{2}}{4} + a x + 2 a - 16}{2 ( x + 2 )}

Join

\frac{x ^{2}}{4} + a x + 2 a - 16 : \frac{x ^{2} + 4 a x + 8 a - 64}{4}

= \frac{\frac{x ^{2} + 4 a x + 8 a - 64}{4}}{2 ( x + 2 )}

Apply the fraction rule:

\frac{\frac{b}{c}}{a} = \frac{b}{c \cdot a}

= \frac{x ^{2} + a x \cdot 4 + 8 a - 64}{4 \cdot 2 ( x + 2 )}

Multiply the numbers:

4 \cdot 2 = 8

= \frac{x ^{2} + 4 a x + 8 a - 64}{8 ( x + 2 )}

- x^{2} - x + 2 = 0

16.5 \cdot \frac{1}{10}

8 x < 24 or x - 4 > 1

\frac{5 k ^{2} - 50 k + 45}{k ^{2} - 18 k + 81}

64 - 4 z^{2}

What is factor ((1/4 x^2+ax+(2a-8)-8))/(2(x+2)) ?
The solution to factor ((1/4 x^2+ax+(2a-8)-8))/(2(x+2)) is (x^2+4ax+8a-64)/(8(x+2))