What is (x^2-4x-5)/(x^2-2x-15) ?

The solution to (x^2-4x-5)/(x^2-2x-15) is (x+1)/(x+3)

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simplify (x^2-4x-5)/(x^2-2x-15)

simplify

\frac{x ^{2} - 4 x - 5}{x ^{2} - 2 x - 15}

\frac{x + 1}{x + 3}

Solution steps

\frac{x ^{2} - 4 x - 5}{x ^{2} - 2 x - 15}

Factor

x^{2} - 4 x - 5 : (x + 1) (x - 5)

= \frac{( x + 1 ) ( x - 5 )}{x ^{2} - 2 x - 15}

Factor

x^{2} - 2 x - 15 : (x + 3) (x - 5)

= \frac{( x + 1 ) ( x - 5 )}{( x + 3 ) ( x - 5 )}

Cancel the common factor:

x - 5

= \frac{x + 1}{x + 3}

510 \cdot 46

(2 x - y) (3 x + 5 y)

- 5 (- 2 x + 7)

4 x^{2} - 40 x y + 100 y^{2}

8 + 1

What is (x^2-4x-5)/(x^2-2x-15) ?
The solution to (x^2-4x-5)/(x^2-2x-15) is (x+1)/(x+3)