What is expand (4x^2-x-7)(x^2-3x+1) ?

The solution to expand (4x^2-x-7)(x^2-3x+1) is 4x^4-13x^3+20x-7

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (4x^2-x-7)(x^2-3x+1)

expand

(4 x^{2} - x - 7) (x^{2} - 3 x + 1)

4 x^{4} - 13 x^{3} + 20 x - 7

Solution steps

(4 x^{2} - x - 7) (x^{2} - 3 x + 1)

Distribute parentheses

= 4 x^{2} x^{2} + 4 x^{2} (- 3 x) + 4 x^{2} \cdot 1 - x x^{2} - x (- 3 x) - x \cdot 1 - 7 x^{2} - 7 (- 3 x) - 7 \cdot 1

Simplify

4 x^{2} x^{2} + 4 x^{2} (- 3 x) + 4 x^{2} \cdot 1 - x x^{2} - x (- 3 x) - x \cdot 1 - 7 x^{2} - 7 (- 3 x) - 7 \cdot 1 : 4 x^{4} - 13 x^{3} + 20 x - 7

= 4 x^{4} - 13 x^{3} + 20 x - 7

\frac{0}{14}

(- 2 - i) (- 2 + i)

8 \cdot 11

8 \cdot 19

4 - 5 - 2 x - 4 y + 4 - 5 x + 7 y

What is expand (4x^2-x-7)(x^2-3x+1) ?
The solution to expand (4x^2-x-7)(x^2-3x+1) is 4x^4-13x^3+20x-7