What is 2yx^{-1}*(x^2)^3 ?

The solution to 2yx^{-1}*(x^2)^3 is 2yx^5

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simplify 2yx^{-1}*(x^2)^3

simplify

2 y x^{- 1} \cdot (x^{2})^{3}

2 y x^{5}

Solution steps

2 y x^{- 1} (x^{2})^{3}

Apply exponent rule:

a^{- 1} = \frac{1}{a}

x^{- 1} = \frac{1}{x}

= 2 y \frac{1}{x} (x^{2})^{3}

Simplify

(x^{2})^{3} : x^{6}

= 2 y \frac{1}{x} x^{6}

Apply the fraction rule:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{2 y \cdot 1 \cdot x ^{6}}{x}

Multiply the numbers:

2 \cdot 1 = 2

= \frac{2 y x ^{6}}{x}

Simplify

\frac{x ^{6}}{x} : x^{5}

= 2 y x^{5}

(5 + y)^{2}

\frac{3}{5} \cdot 200

(2 x - 3) (3 x - 1)

(- 3 x^{3} y^{2} z^{6})^{2}

24 x^{4}