What are the solutions to the equation -x^2+5x-7=0 ?

The solutions to the equation -x^2+5x-7=0 are x= 5/2-i(sqrt(3))/2 ,x= 5/2+i(sqrt(3))/2

Find the zeros of -x^2+5x-7=0

The zeros of -x^2+5x-7=0 are x= 5/2-i(sqrt(3))/2 ,x= 5/2+i(sqrt(3))/2

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- x^{2} + 5 x - 7 = 0

x = \frac{5}{2} - i \frac{3}{2}, x = \frac{5}{2} + i \frac{3}{2}

Solution steps

- x^{2} + 5 x - 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 ( - 1 ) ( - 7 )}{2 ( - 1 )}

Simplify

5^{2} - 4 (- 1) (- 7) : 3 i

x_{1, 2} = \frac{- 5 \pm 3 i}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 5 + 3 i}{2 ( - 1 )}, x_{2} = \frac{- 5 - 3 i}{2 ( - 1 )}

x = \frac{- 5 + 3 i}{2 ( - 1 )} : \frac{5}{2} - i \frac{3}{2}

x = \frac{- 5 - 3 i}{2 ( - 1 )} : \frac{5}{2} + i \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} - i \frac{3}{2}, x = \frac{5}{2} + i \frac{3}{2}

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What are the solutions to the equation -x^2+5x-7=0 ?
The solutions to the equation -x^2+5x-7=0 are x= 5/2-i(sqrt(3))/2 ,x= 5/2+i(sqrt(3))/2
Find the zeros of -x^2+5x-7=0
The zeros of -x^2+5x-7=0 are x= 5/2-i(sqrt(3))/2 ,x= 5/2+i(sqrt(3))/2