What is (x+8)^2-4(x+8)-1 ?

The solution to (x+8)^2-4(x+8)-1 is x^2+12x+31

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simplify (x+8)^2-4(x+8)-1

simplify

(x + 8)^{2} - 4 (x + 8) - 1

x^{2} + 12 x + 31

Solution steps

(x + 8)^{2} - 4 (x + 8) - 1

Expand

(x + 8)^{2} : x^{2} + 16 x + 64

= x^{2} + 16 x + 64 - 4 (x + 8) - 1

Expand

- 4 (x + 8) : - 4 x - 32

= x^{2} + 16 x + 64 - 4 x - 32 - 1

Group like terms

= x^{2} + 16 x - 4 x + 64 - 32 - 1

Add similar elements:

16 x - 4 x = 12 x

= x^{2} + 12 x + 64 - 32 - 1

Subtract the numbers:

64 - 32 - 1 = 31

= x^{2} + 12 x + 31

∣ 4 - 8 ∣

\frac{- 6}{- 9}

3 (p - 2 q) - 4 (2 p - 3 q - 5)

4 + 6 (a c + 2 b) + 2 a c

\frac{47}{24}