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Popular >

factor 16x^4-8x^2+1

Solution

factor

16 x^{4} - 8 x^{2} + 1

Solution

(2 x + 1)^{2} (2 x - 1)^{2}

Solution steps

16 x^{4} - 8 x^{2} + 1

Let

u = x^{2}

= 16 u^{2} - 8 u + 1

Factor

16 u^{2} - 8 u + 1 : (4 u - 1)^{2}

= (4 u - 1)^{2}

Substitute back

u = x^{2}

= (4 x^{2} - 1)^{2}

Factor

4 x^{2} - 1 : (2 x + 1) (2 x - 1)

= ((2 x + 1) (2 x - 1))^{2}

Apply exponent rule:

(a \cdot b)^{n} = a^{n} b^{n}

((2 x + 1) (2 x - 1))^{2} = (2 x + 1)^{2} (2 x - 1)^{2}

= (2 x + 1)^{2} (2 x - 1)^{2}

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Frequently Asked Questions (FAQ)

What is factor 16x^4-8x^2+1 ?
The solution to factor 16x^4-8x^2+1 is (2x+1)^2(2x-1)^2