What is ((2x^3y^2)/(3xy))^{-3} ?

The solution to ((2x^3y^2)/(3xy))^{-3} is (27)/(8x^6y^3)

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simplify ((2x^3y^2)/(3xy))^{-3}

simplify

(\frac{2 x ^{3} y ^{2}}{3 x y})^{- 3}

\frac{27}{8 x ^{6} y ^{3}}

Solution steps

(\frac{2 x ^{3} y ^{2}}{3 x y})^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(\frac{2 x ^{3} y ^{2}}{3 x y})^{- 3} = \frac{1}{( \frac{2 x ^{3} y ^{2}}{3 x y} ) ^{3}}

= \frac{1}{( \frac{2 x ^{3} y ^{2}}{3 x y} ) ^{3}}

Simplify

(\frac{2 x ^{3} y ^{2}}{3 x y})^{3} : \frac{8 x ^{6} y ^{3}}{27}

= \frac{1}{\frac{8 x ^{6} y ^{3}}{27}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{27}{8 x ^{6} y ^{3}}

\frac{1}{5} \cdot 25

3.64 + \frac{3}{5}

f (- 4) - g (2)

(3 x + 2) (4 x + 5)

What is ((2x^3y^2)/(3xy))^{-3} ?
The solution to ((2x^3y^2)/(3xy))^{-3} is (27)/(8x^6y^3)