What is (3x^{-4})^{-2}x^{-2} ?

The solution to (3x^{-4})^{-2}x^{-2} is (x^6)/9

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simplify (3x^{-4})^{-2}x^{-2}

simplify

(3 x^{- 4})^{- 2} x^{- 2}

\frac{x ^{6}}{9}

Solution steps

(3 x^{- 4})^{- 2} x^{- 2}

Simplify

(3 x^{- 4})^{- 2} : \frac{x ^{8}}{9}

= \frac{x ^{8}}{9} x^{- 2}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 2} = \frac{1}{x ^{2}}

= \frac{x ^{8}}{9} \cdot \frac{1}{x ^{2}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{8} \cdot 1}{9 x ^{2}}

Apply rule:

a \cdot 1 = a

x^{8} \cdot 1 = x^{8}

= \frac{x ^{8}}{9 x ^{2}}

Simplify

\frac{x ^{8}}{x ^{2}} : x^{6}

= \frac{x ^{6}}{9}

(a + b + 1)^{2}

π \cdot \frac{180}{π}

\frac{2 x}{x + 9} - \frac{x - 1}{x}

\frac{11}{- 1}

3 \cdot 5 \cdot 7