What is 1/(\sqrt[3]{8y^2)} ?

The solution to 1/(\sqrt[3]{8y^2)} is 1/(2\sqrt[3]{y^2)}

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simplify 1/(\sqrt[3]{8y^2)}

simplify

Solution steps

Apply radical rule:

assuming

a \geq 0, b \geq 0

2 x^{2} (3 x^{2} + 2 x y^{2} - 7 x)

(\frac{x}{x + 1})^{2}

3 (x + 9) + 5 (4 x - 6)

3 a \cdot 2 a

\frac{2}{7} \div \frac{8}{3}

What is 1/(\sqrt[3]{8y^2)} ?
The solution to 1/(\sqrt[3]{8y^2)} is 1/(2\sqrt[3]{y^2)}