What are the solutions to the equation x^2-49=48x ?

The solutions to the equation x^2-49=48x are x=49,x=-1

Find the zeros of x^2-49=48x

The zeros of x^2-49=48x are x=49,x=-1

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x^{2} - 49 = 48 x

x = 49, x = - 1

Solution steps

x^{2} - 49 = 48 x

Move

48 x

to the left side

x^{2} - 49 - 48 x = 0

Write in the standard form

a x^{2} + b x + c = 0

x^{2} - 48 x - 49 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 48 ) \pm ( - 48 ) ^{2} - 4 \cdot 1 \cdot ( - 49 )}{2 \cdot 1}

(- 48)^{2} - 4 \cdot 1 \cdot (- 49) = 50

x_{1, 2} = \frac{- ( - 48 ) \pm 50}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 48 ) + 50}{2 \cdot 1}, x_{2} = \frac{- ( - 48 ) - 50}{2 \cdot 1}

x = \frac{- ( - 48 ) + 50}{2 \cdot 1} : 49

x = \frac{- ( - 48 ) - 50}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 49, x = - 1

\frac{3 6 + 5 2}{4 6 - 3 2}

3 (4 + 12 x) - 6 (2 x + 3) = 36 + 2 (3 x + 2)

x^{2} - 100 \geq 0

∣ y - 5 ∣ > 3

8 a - 15 = - 3

What are the solutions to the equation x^2-49=48x ?
The solutions to the equation x^2-49=48x are x=49,x=-1
Find the zeros of x^2-49=48x
The zeros of x^2-49=48x are x=49,x=-1