What is factor p^6+8q^3 ?

The solution to factor p^6+8q^3 is (p^2+2q)(p^4-2p^2q+4q^2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

factor p^6+8q^3

factor

p^{6} + 8 q^{3}

(p^{2} + 2 q) (p^{4} - 2 p^{2} q + 4 q^{2})

Solution steps

p^{6} + 8 q^{3}

Apply exponent rules

= (p^{2})^{3} + (2 q)^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(p^{2})^{3} + (2 q)^{3} = (p^{2} + 2 q) ((p^{2})^{2} - p^{2} \cdot 2 q + (2 q)^{2})

= (p^{2} + 2 q) ((p^{2})^{2} - p^{2} \cdot 2 q + (2 q)^{2})

Simplify

(p^{2})^{2} - p^{2} \cdot 2 q + (2 q)^{2} : p^{4} - 2 p^{2} q + 4 q^{2}

= (p^{2} + 2 q) (p^{4} - 2 p^{2} q + 4 q^{2})

13 \cdot (- 3)

\frac{( 3 + h ) ^{3} - 27}{h}

2 \cdot (- 2^{2})

(n + 5)^{2}

\frac{- ( 4 m ^{2} n )}{- m ^{2} n ^{6}}

What is factor p^6+8q^3 ?
The solution to factor p^6+8q^3 is (p^2+2q)(p^4-2p^2q+4q^2)