What is expand (2x+3)(x^2-5x+4) ?

The solution to expand (2x+3)(x^2-5x+4) is 2x^3-7x^2-7x+12

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (2x+3)(x^2-5x+4)

expand

(2 x + 3) (x^{2} - 5 x + 4)

2 x^{3} - 7 x^{2} - 7 x + 12

Solution steps

(2 x + 3) (x^{2} - 5 x + 4)

Distribute parentheses

= 2 x x^{2} + 2 x (- 5 x) + 2 x \cdot 4 + 3 x^{2} + 3 (- 5 x) + 3 \cdot 4

Simplify

2 x x^{2} + 2 x (- 5 x) + 2 x \cdot 4 + 3 x^{2} + 3 (- 5 x) + 3 \cdot 4 : 2 x^{3} - 7 x^{2} - 7 x + 12

= 2 x^{3} - 7 x^{2} - 7 x + 12

3.5 \cdot (5.8 - 7.09)

x^{2} x x^{2}

x + 7^{2}

\frac{2 + 3 x}{16 - 81 x ^{4}}

6 x^{2} \cdot 42 x

What is expand (2x+3)(x^2-5x+4) ?
The solution to expand (2x+3)(x^2-5x+4) is 2x^3-7x^2-7x+12