What is (2n-1}{2n}-\frac{3n-2)/4 ?

The solution to (2n-1}{2n}-\frac{3n-2)/4 is (-3n^2+6n-2)/(4n)

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simplify (2n-1}{2n}-\frac{3n-2)/4

simplify

\frac{2 n - 1}{2 n} - \frac{3 n - 2}{4}

\frac{- 3 n ^{2} + 6 n - 2}{4 n}

Solution steps

\frac{2 n - 1}{2 n} - \frac{3 n - 2}{4}

Least Common Multiplier of

2 n, 4 : 4 n

Adjust Fractions based on the LCM

= \frac{( 2 n - 1 ) \cdot 2}{4 n} - \frac{( 3 n - 2 ) n}{4 n}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{( 2 n - 1 ) \cdot 2 - ( 3 n - 2 ) n}{4 n}

Simplify

(2 n - 1) \cdot 2 - (3 n - 2) n : - 3 n^{2} + 6 n - 2

= \frac{- 3 n ^{2} + 6 n - 2}{4 n}

\frac{16}{- 1}

\frac{7}{\frac{1}{x - 6}} + 6

\frac{7}{36}

12 g + 6 f - 2 f - 5 g - 4 f

x^{4^{2}}

What is (2n-1}{2n}-\frac{3n-2)/4 ?
The solution to (2n-1}{2n}-\frac{3n-2)/4 is (-3n^2+6n-2)/(4n)