What is factor 2x^5-x^4-32x+16 ?

The solution to factor 2x^5-x^4-32x+16 is (2x-1)(x^2+4)(x+2)(x-2)

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factor 2x^5-x^4-32x+16

factor

2 x^{5} - x^{4} - 32 x + 16

(2 x - 1) (x^{2} + 4) (x + 2) (x - 2)

Solution steps

2 x^{5} - x^{4} - 32 x + 16

= (2 x^{5} - x^{4}) + (- 32 x + 16)

Factor out

x^{4}

from

2 x^{5} - x^{4} : x^{4} (2 x - 1)

Factor out

- 16

from

- 32 x + 16 : - 16 (2 x - 1)

= x^{4} (2 x - 1) - 16 (2 x - 1)

Factor out common term

2 x - 1

= (2 x - 1) (x^{4} - 16)

Factor

x^{4} - 16 : (x^{2} + 4) (x + 2) (x - 2)

= (2 x - 1) (x^{2} + 4) (x + 2) (x - 2)

(9 x - 7)^{2}

\frac{3}{7} - \frac{2}{7}

(a^{2} - 2 ab + 4 b^{2}) (a + 2 b)

(a^{3} b^{4} c^{6}) (4 a c^{3})^{2}

a^{2} - a + 4 a - 3 a^{2} + 1

What is factor 2x^5-x^4-32x+16 ?
The solution to factor 2x^5-x^4-32x+16 is (2x-1)(x^2+4)(x+2)(x-2)