What is expand 4x^2(2x^3+x^2-3) ?

The solution to expand 4x^2(2x^3+x^2-3) is 8x^5+4x^4-12x^2

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expand 4x^2(2x^3+x^2-3)

expand

4 x^{2} (2 x^{3} + x^{2} - 3)

8 x^{5} + 4 x^{4} - 12 x^{2}

Solution steps

4 x^{2} (2 x^{3} + x^{2} - 3)

Apply the distributive law:

m (a + b + c) = ma + mb + m c

4 x^{2} (2 x^{3} + x^{2} - 3) = 4 x^{2} \cdot 2 x^{3} + 4 x^{2} x^{2} + 4 x^{2} (- 3)

= 4 x^{2} \cdot 2 x^{3} + 4 x^{2} x^{2} + 4 x^{2} (- 3)

Simplify

4 x^{2} \cdot 2 x^{3} + 4 x^{2} x^{2} + 4 x^{2} (- 3) : 8 x^{5} + 4 x^{4} - 12 x^{2}

= 8 x^{5} + 4 x^{4} - 12 x^{2}

\frac{cos ( 2 x )}{cos ^{2} ( x )}

\frac{8.9 - 9}{8.9 - 3}

3 x - 2 y (4)

\frac{2}{3} \div \frac{5}{8}

15 x - 2 x - (13 x + 10 x)

What is expand 4x^2(2x^3+x^2-3) ?
The solution to expand 4x^2(2x^3+x^2-3) is 8x^5+4x^4-12x^2