What are the solutions to the equation (x^2+2)=0 ?

The solutions to the equation (x^2+2)=0 are x=sqrt(2)i,x=-sqrt(2)i

Find the zeros of (x^2+2)=0

The zeros of (x^2+2)=0 are x=sqrt(2)i,x=-sqrt(2)i

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(x^{2} + 2) = 0

x = 2 i, x = - 2 i

Solution steps

(x^{2} + 2) = 0

x^{2} + 2 = 0

Move

2

to the right side

x^{2} = - 2

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 2, x = - - 2

- 2 = 2 i

- - 2 = - 2 i

x = 2 i, x = - 2 i

\frac{1}{12} - (\frac{3}{8} - \frac{11}{4})

- 5 w \leq 15

10 z^{2} + 11 z - 6

15 d^{2} + 72 d - 15

f = \frac{( - 2 ) ^{2} - 5 ( - 2 ) - 24}{( - 2 ) ^{2} - 1}

What are the solutions to the equation (x^2+2)=0 ?
The solutions to the equation (x^2+2)=0 are x=sqrt(2)i,x=-sqrt(2)i
Find the zeros of (x^2+2)=0
The zeros of (x^2+2)=0 are x=sqrt(2)i,x=-sqrt(2)i