What are the solutions to the equation 5x^2-9x+10=0 ?

The solutions to the equation 5x^2-9x+10=0 are x= 9/10+i(sqrt(119))/(10),x= 9/10-i(sqrt(119))/(10)

Find the zeros of 5x^2-9x+10=0

The zeros of 5x^2-9x+10=0 are x= 9/10+i(sqrt(119))/(10),x= 9/10-i(sqrt(119))/(10)

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5 x^{2} - 9 x + 10 = 0

x = \frac{9}{10} + i \frac{119}{10}, x = \frac{9}{10} - i \frac{119}{10}

Solution steps

5 x^{2} - 9 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

Simplify

(- 9)^{2} - 4 \cdot 5 \cdot 10 : 119 i

x_{1, 2} = \frac{- ( - 9 ) \pm 119 i}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 9 ) + 119 i}{2 \cdot 5}, x_{2} = \frac{- ( - 9 ) - 119 i}{2 \cdot 5}

x = \frac{- ( - 9 ) + 119 i}{2 \cdot 5} : \frac{9}{10} + i \frac{119}{10}

x = \frac{- ( - 9 ) - 119 i}{2 \cdot 5} : \frac{9}{10} - i \frac{119}{10}

The solutions to the quadratic equation are:

x = \frac{9}{10} + i \frac{119}{10}, x = \frac{9}{10} - i \frac{119}{10}

1 0^{- 2.7}

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c + 5 < 6

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What are the solutions to the equation 5x^2-9x+10=0 ?
The solutions to the equation 5x^2-9x+10=0 are x= 9/10+i(sqrt(119))/(10),x= 9/10-i(sqrt(119))/(10)
Find the zeros of 5x^2-9x+10=0
The zeros of 5x^2-9x+10=0 are x= 9/10+i(sqrt(119))/(10),x= 9/10-i(sqrt(119))/(10)