What is 2(x+1)^2-5(x+1)-7 ?

The solution to 2(x+1)^2-5(x+1)-7 is 2x^2-x-10

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simplify 2(x+1)^2-5(x+1)-7

simplify

2 (x + 1)^{2} - 5 (x + 1) - 7

2 x^{2} - x - 10

Solution steps

2 (x + 1)^{2} - 5 (x + 1) - 7

Expand

2 (x + 1)^{2} : 2 x^{2} + 4 x + 2

= 2 x^{2} + 4 x + 2 - 5 (x + 1) - 7

Expand

- 5 (x + 1) : - 5 x - 5

= 2 x^{2} + 4 x + 2 - 5 x - 5 - 7

Group like terms

= 2 x^{2} + 4 x - 5 x + 2 - 5 - 7

Add similar elements:

4 x - 5 x = - x

= 2 x^{2} - x + 2 - 5 - 7

Subtract the numbers:

2 - 5 - 7 = - 10

= 2 x^{2} - x - 10

- \frac{1}{16}

\frac{y ^{- 4}}{5 x ^{- 2}}

9 n - 8 + 3 (2 n - 11)

ln (x^{2} + 1)

\frac{- 30}{5}