What is factor 4n^2+4n-3 ?

The solution to factor 4n^2+4n-3 is (2n-1)(2n+3)

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factor 4n^2+4n-3

factor

4 n^{2} + 4 n - 3

(2 n - 1) (2 n + 3)

Solution steps

4 n^{2} + 4 n - 3

Break the expression into groups

= (4 n^{2} - 2 n) + (6 n - 3)

Factor out

2 n

from

4 n^{2} - 2 n : 2 n (2 n - 1)

Factor out

3

from

6 n - 3 : 3 (2 n - 1)

= 2 n (2 n - 1) + 3 (2 n - 1)

Factor out common term

2 n - 1

= (2 n - 1) (2 n + 3)

\frac{2 x}{4 x ^{3}}

(2 x + y^{3})^{2}

- 9.4 \cdot 2.7

∣ - 1 - 1 ∣

- 9 \cdot 12