What is ((x^3-8))/((x^2-4)) ?

The solution to ((x^3-8))/((x^2-4)) is (x^2+2x+4)/(x+2)

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simplify ((x^3-8))/((x^2-4))

simplify

\frac{( x ^{3} - 8 )}{( x ^{2} - 4 )}

\frac{x ^{2} + 2 x + 4}{x + 2}

Solution steps

\frac{x ^{3} - 8}{x ^{2} - 4}

Factor

x^{3} - 8 : (x - 2) (x^{2} + 2 x + 4)

= \frac{( x - 2 ) ( x ^{2} + 2 x + 4 )}{x ^{2} - 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x - 2 ) ( x ^{2} + 2 x + 4 )}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{x ^{2} + 2 x + 4}{x + 2}

(2 x^{2} y^{5})^{3}

- 20 + 2

- 20 + 8

(- 15) \cdot (2.1)

10 \div \frac{1}{5}

What is ((x^3-8))/((x^2-4)) ?
The solution to ((x^3-8))/((x^2-4)) is (x^2+2x+4)/(x+2)