What is (3x^2+7x)+(2x^2-x-1) ?

The solution to (3x^2+7x)+(2x^2-x-1) is 5x^2+6x-1

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simplify (3x^2+7x)+(2x^2-x-1)

simplify

(3 x^{2} + 7 x) + (2 x^{2} - x - 1)

5 x^{2} + 6 x - 1

Solution steps

(3 x^{2} + 7 x) + (2 x^{2} - x - 1)

Simplify

(3 x^{2} + 7 x) + (2 x^{2} - x - 1) : 3 x^{2} + 7 x + 2 x^{2} - x - 1

= 3 x^{2} + 7 x + 2 x^{2} - x - 1

Group like terms

= 3 x^{2} + 2 x^{2} + 7 x - x - 1

Add similar elements:

3 x^{2} + 2 x^{2} = 5 x^{2}

= 5 x^{2} + 7 x - x - 1

Add similar elements:

7 x - x = 6 x

= 5 x^{2} + 6 x - 1

f^{6} - 400

6 a^{2} b^{2} + 5 ab - 25

(- 1 + 2 i) (- 1 - 2 i)

(u - 1)^{4}

\frac{4}{7} \div \frac{7}{2}

What is (3x^2+7x)+(2x^2-x-1) ?
The solution to (3x^2+7x)+(2x^2-x-1) is 5x^2+6x-1