What is factor a^2-26a+169 ?

The solution to factor a^2-26a+169 is (a-13)^2

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factor a^2-26a+169

factor

a^{2} - 26 a + 169

(a - 13)^{2}

Solution steps

a^{2} - 26 a + 169

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

169 = 1 3^{2}

- 26 a = - 2 a \cdot 13

= a^{2} - 2 a \cdot 13 + 1 3^{2}

Apply Perfect Square Formula:

a^{2} - 2 ab + b^{2} = (a - b)^{2}

a^{2} - 2 a \cdot 13 + 1 3^{2} = (a - 13)^{2}

= (a - 13)^{2}

\frac{19}{95}

(- 3 x y)^{2} (- 2 x^{2} y)^{3}

\frac{x ^{2} - 8 x + 15}{x ^{2} - 5 x + 6}

34.46 + \frac{50}{40}

(2 + 5) (- 2 + 5 k)