What is factor 1-16x^8 ?

The solution to factor 1-16x^8 is -(2x^2+2x+1)(2x^2-2x+1)(2x^2+1)(2x^2-1)

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factor 1-16x^8

factor

1 - 16 x^{8}

- (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1) (2 x^{2} + 1) (2 x^{2} - 1)

Solution steps

1 - 16 x^{8}

Write in the standard form

= - 16 x^{8} + 1

Factor out

- 1 : - (16 x^{8} - 1)

= - (16 x^{8} - 1)

Factor

16 x^{8} - 1 : (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1) (2 x^{2} + 1) (2 x^{2} - 1)

= - (2 x^{2} + 2 x + 1) (2 x^{2} - 2 x + 1) (2 x^{2} + 1) (2 x^{2} - 1)

\frac{5}{12}

\frac{m ^{- 6}}{m ^{5}}

2 x^{3} + x

(4 n + 6) (8 n + 8)

\frac{8.999 - 9}{8.999 - 3}

What is factor 1-16x^8 ?
The solution to factor 1-16x^8 is -(2x^2+2x+1)(2x^2-2x+1)(2x^2+1)(2x^2-1)