What is [(x^9y^{-9})^{-1}]^{-1} ?

The solution to [(x^9y^{-9})^{-1}]^{-1} is (x^9)/(y^9)

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simplify [(x^9y^{-9})^{-1}]^{-1}

simplify

[(x^{9} y^{- 9})^{- 1}]^{- 1}

\frac{x ^{9}}{y ^{9}}

Solution steps

((x^{9} y^{- 9})^{- 1})^{- 1}

Apply exponent rule:

(a^{b})^{c} = a^{b c},

assuming

a \geq 0

= (x^{9} y^{- 9})^{- 1 \cdot (- 1)}

- 1 \cdot (- 1) = 1

= (x^{9} y^{- 9})^{1}

Apply exponent rule:

a^{1} = a

= x^{9} y^{- 9}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

y^{- 9} = \frac{1}{y ^{9}}

= \frac{1}{y ^{9}} x^{9}

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= \frac{1 \cdot x ^{9}}{y ^{9}}

Multiply:

1 \cdot x^{9} = x^{9}

= \frac{x ^{9}}{y ^{9}}

81 y^{6}

\frac{x ^{4} + 2 x ^{3} + x ^{2}}{x + 1}

cos (t) cos (t)

- 24 y - 6 x^{3} y^{2} z^{3}

What is [(x^9y^{-9})^{-1}]^{-1} ?
The solution to [(x^9y^{-9})^{-1}]^{-1} is (x^9)/(y^9)