What is (2x^{-3})^{-4}x^{-4} ?

The solution to (2x^{-3})^{-4}x^{-4} is (x^8)/(16)

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simplify (2x^{-3})^{-4}x^{-4}

simplify

(2 x^{- 3})^{- 4} x^{- 4}

\frac{x ^{8}}{16}

Solution steps

(2 x^{- 3})^{- 4} x^{- 4}

Simplify

(2 x^{- 3})^{- 4} : \frac{x ^{12}}{16}

= \frac{x ^{12}}{16} x^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

x^{- 4} = \frac{1}{x ^{4}}

= \frac{x ^{12}}{16} \cdot \frac{1}{x ^{4}}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{x ^{12} \cdot 1}{16 x ^{4}}

Apply rule:

a \cdot 1 = a

x^{12} \cdot 1 = x^{12}

= \frac{x ^{12}}{16 x ^{4}}

Simplify

\frac{x ^{12}}{x ^{4}} : x^{8}

= \frac{x ^{8}}{16}

1 + \frac{2}{x + 2}

(\frac{4 ^{3}}{y})^{3}

- 25 - - 4

\frac{3}{3 - 2}

\frac{- 1}{2} - \frac{1}{2}

What is (2x^{-3})^{-4}x^{-4} ?
The solution to (2x^{-3})^{-4}x^{-4} is (x^8)/(16)