What is log_{4}(81)-log_{2}(3) ?

The solution to log_{4}(81)-log_{2}(3) is 4log_{4}(3)-log_{2}(3)

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simplify log_{4}(81)-log_{2}(3)

simplify

lo g_{4} (81) - lo g_{2} (3)

4 lo g_{4} (3) - lo g_{2} (3)

Decimal Notation

1.58496 \dots

Solution steps

lo g_{4} (81) - lo g_{2} (3)

lo g_{4} (81) = 4 lo g_{4} (3)

= 4 lo g_{4} (3) - lo g_{2} (3)

a \cdot 1

\frac{7}{3} - \frac{2}{5}

6 (x + 6) - (x - 6)

5 x^{3} 2 x^{2}

7^{2} + 1^{2}

What is log_{4}(81)-log_{2}(3) ?
The solution to log_{4}(81)-log_{2}(3) is 4log_{4}(3)-log_{2}(3)