What are the solutions to the equation 15x^2+26x+8=0 ?

The solutions to the equation 15x^2+26x+8=0 are x=-2/5 ,x=-4/3

Find the zeros of 15x^2+26x+8=0

The zeros of 15x^2+26x+8=0 are x=-2/5 ,x=-4/3

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15 x^{2} + 26 x + 8 = 0

x = - \frac{2}{5}, x = - \frac{4}{3}

Solution steps

15 x^{2} + 26 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 26 \pm 2 6 ^{2} - 4 \cdot 15 \cdot 8}{2 \cdot 15}

2 6^{2} - 4 \cdot 15 \cdot 8 = 14

x_{1, 2} = \frac{- 26 \pm 14}{2 \cdot 15}

Separate the solutions

x_{1} = \frac{- 26 + 14}{2 \cdot 15}, x_{2} = \frac{- 26 - 14}{2 \cdot 15}

x = \frac{- 26 + 14}{2 \cdot 15} : - \frac{2}{5}

x = \frac{- 26 - 14}{2 \cdot 15} : - \frac{4}{3}

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - \frac{4}{3}

7 x^{2} - 6 x + 1 = 0

x^{3} + 2 x^{2} + 3 x + 6

∣ 2 x - 9 ∣ = 19

\frac{2 x h + h ^{2}}{h}

\frac{5 - x}{12} = - 7

What are the solutions to the equation 15x^2+26x+8=0 ?
The solutions to the equation 15x^2+26x+8=0 are x=-2/5 ,x=-4/3
Find the zeros of 15x^2+26x+8=0
The zeros of 15x^2+26x+8=0 are x=-2/5 ,x=-4/3