What are the solutions to the equation d^2+16=60 ?

The solutions to the equation d^2+16=60 are d=2sqrt(11),d=-2sqrt(11)

Find the zeros of d^2+16=60

The zeros of d^2+16=60 are d=2sqrt(11),d=-2sqrt(11)

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d^{2} + 16 = 60

d = 211, d = - 211

Decimal Notation

d = 6.63324 \dots, d = - 6.63324 \dots

Solution steps

d^{2} + 16 = 60

Move

16

to the right side

d^{2} = 44

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

d = 44, d = - 44

44 = 211

- 44 = - 211

d = 211, d = - 211

\frac{1}{3} - \frac{1}{1}

\frac{5}{x - 1} < 3

25 - 6 k = - 6 (k - 3)

(- 8)^{- \frac{2}{3}}

\frac{8 x + 7}{6} = \frac{5 x + 2}{7}

What are the solutions to the equation d^2+16=60 ?
The solutions to the equation d^2+16=60 are d=2sqrt(11),d=-2sqrt(11)
Find the zeros of d^2+16=60
The zeros of d^2+16=60 are d=2sqrt(11),d=-2sqrt(11)