What is expand (3x^{4a-5}+2y^{2a+1})^2 ?

The solution to expand (3x^{4a-5}+2y^{2a+1})^2 is (3x^{4a-5})^2+12x^{4a-5}y^{2a+1}+(2y^{2a+1})^2

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expand (3x^{4a-5}+2y^{2a+1})^2

expand

(3 x^{4 a - 5} + 2 y^{2 a + 1})^{2}

(3 x^{4 a - 5})^{2} + 12 x^{4 a - 5} y^{2 a + 1} + (2 y^{2 a + 1})^{2}

Solution steps

(3 x^{4 a - 5} + 2 y^{2 a + 1})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(3 x^{4 a - 5} + 2 y^{2 a + 1})^{2} = (3 x^{4 a - 5})^{2} + 2 \cdot 3 x^{4 a - 5} \cdot 2 y^{2 a + 1} + (2 y^{2 a + 1})^{2}

= (3 x^{4 a - 5})^{2} + 2 \cdot 3 x^{4 a - 5} \cdot 2 y^{2 a + 1} + (2 y^{2 a + 1})^{2}

Multiply the numbers:

2 \cdot 3 \cdot 2 = 12

= (3 x^{4 a - 5})^{2} + 12 x^{4 a - 5} y^{2 a + 1} + (2 y^{2 a + 1})^{2}

\frac{3 x - 3}{x - 1}

3700

2 \cdot 26

46 \cdot 3

\frac{4}{5 + 3}

What is expand (3x^{4a-5}+2y^{2a+1})^2 ?
The solution to expand (3x^{4a-5}+2y^{2a+1})^2 is (3x^{4a-5})^2+12x^{4a-5}y^{2a+1}+(2y^{2a+1})^2