What is (\sqrt[3]{-2x^3y})^4 ?

The solution to (\sqrt[3]{-2x^3y})^4 is 2\sqrt[3]{2}x^4y\sqrt[3]{y}

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simplify (\sqrt[3]{-2x^3y})^4

simplify

Solution steps

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

Apply exponent rule:

assuming

n i s o dd or a \geq 0

Simplify

Apply rule:

- a (- b) = ab

Simplify

x^{3} x : x^{4}

\frac{7}{3} \cdot \frac{3}{10}

(3 + 4 i) (2 - i)

10 x - x

- 1. 6^{2}

25 z^{2} - 30 z + 9

What is (\sqrt[3]{-2x^3y})^4 ?
The solution to (\sqrt[3]{-2x^3y})^4 is 2\sqrt[3]{2}x^4y\sqrt[3]{y}