What are the solutions to the equation 9x^2+54x=0 ?

The solutions to the equation 9x^2+54x=0 are x=0,x=-6

Find the zeros of 9x^2+54x=0

The zeros of 9x^2+54x=0 are x=0,x=-6

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9 x^{2} + 54 x = 0

x = 0, x = - 6

Solution steps

9 x^{2} + 54 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 54 \pm 5 4 ^{2} - 4 \cdot 9 \cdot 0}{2 \cdot 9}

5 4^{2} - 4 \cdot 9 \cdot 0 = 54

x_{1, 2} = \frac{- 54 \pm 54}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 54 + 54}{2 \cdot 9}, x_{2} = \frac{- 54 - 54}{2 \cdot 9}

x = \frac{- 54 + 54}{2 \cdot 9} : 0

x = \frac{- 54 - 54}{2 \cdot 9} : - 6

The solutions to the quadratic equation are:

x = 0, x = - 6

81 a^{36} - 64 b^{16}

5 n^{6} + 2 n^{5}

- 6 (1 + 6 x) < 6 (1 - 5 x)

\frac{\frac{1}{a} + \frac{1}{a + 1}}{\frac{1}{a} - \frac{1}{a + 1}}

∣ x - 1 ∣ + ∣ x + 1 ∣ < 5

What are the solutions to the equation 9x^2+54x=0 ?
The solutions to the equation 9x^2+54x=0 are x=0,x=-6
Find the zeros of 9x^2+54x=0
The zeros of 9x^2+54x=0 are x=0,x=-6