What is (x^2-1)/((x+1)^2) ?

The solution to (x^2-1)/((x+1)^2) is (x-1)/(x+1)

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simplify (x^2-1)/((x+1)^2)

simplify

\frac{x ^{2} - 1}{( x + 1 ) ^{2}}

\frac{x - 1}{x + 1}

Solution steps

\frac{x ^{2} - 1}{( x + 1 ) ^{2}}

Factor

x^{2} - 1 : (x + 1) (x - 1)

= \frac{( x + 1 ) ( x - 1 )}{( x + 1 ) ^{2}}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 1)^{2} = (x + 1) (x + 1)

= \frac{( x + 1 ) ( x - 1 )}{( x + 1 ) ( x + 1 )}

Cancel the common factor:

x + 1

= \frac{x - 1}{x + 1}

2 x^{2} + 12 x + 8

9 \frac{4}{5}

- 4 x^{2} (x^{2} + 8)

(x) (3 x - 5)

(2 - 3 i) \cdot (2 + 3 i)