What are the solutions to the equation 0=-(x+3)^2+1 ?

The solutions to the equation 0=-(x+3)^2+1 are x=-2,x=-4

Find the zeros of 0=-(x+3)^2+1

The zeros of 0=-(x+3)^2+1 are x=-2,x=-4

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0 = - (x + 3)^{2} + 1

x = - 2, x = - 4

Solution steps

0 = - (x + 3)^{2} + 1

Switch sides

- (x + 3)^{2} + 1 = 0

Move

1

to the right side

- (x + 3)^{2} = - 1

Divide both sides by

- 1

(x + 3)^{2} = 1

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x + 3 = 1 : x = - 2

Solve

x + 3 = - 1 : x = - 4

The solutions to the quadratic equation are:

x = - 2, x = - 4

(- 4)^{- \frac{1}{2}}

3 x - 2 < 1

\frac{2 + x}{3} < 3

6 x^{2} - 3 x - 18

11 d - 8 d = 9

What are the solutions to the equation 0=-(x+3)^2+1 ?
The solutions to the equation 0=-(x+3)^2+1 are x=-2,x=-4
Find the zeros of 0=-(x+3)^2+1
The zeros of 0=-(x+3)^2+1 are x=-2,x=-4