What is (3x^{-2}y^{-3})^{-4} ?

The solution to (3x^{-2}y^{-3})^{-4} is (x^8y^{12})/(81)

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simplify (3x^{-2}y^{-3})^{-4}

simplify

(3 x^{- 2} y^{- 3})^{- 4}

\frac{x ^{8} y ^{12}}{81}

Solution steps

(3 x^{- 2} y^{- 3})^{- 4}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

(3 x^{- 2} y^{- 3})^{- 4} = \frac{1}{( 3 x ^{- 2} y ^{- 3} ) ^{4}}

= \frac{1}{( 3 x ^{- 2} y ^{- 3} ) ^{4}}

Simplify

(3 x^{- 2} y^{- 3})^{4} : \frac{81}{x ^{8} y ^{12}}

= \frac{1}{\frac{81}{x ^{8} y ^{12}}}

Apply the fraction rule:

\frac{1}{\frac{b}{c}} = \frac{c}{b}

= \frac{x ^{8} y ^{12}}{81}

\frac{9}{10} - \frac{1}{10}

(x + 3) (x + 11)

\frac{7}{3} + 3

(10 a + 12 b - 3 c) - (7 a + 6 c - 9 d)

3 x (yz)^{0}

What is (3x^{-2}y^{-3})^{-4} ?
The solution to (3x^{-2}y^{-3})^{-4} is (x^8y^{12})/(81)