What is (x^2-3x+2)/(x^2-4) ?

The solution to (x^2-3x+2)/(x^2-4) is (x-1)/(x+2)

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simplify (x^2-3x+2)/(x^2-4)

simplify

\frac{x ^{2} - 3 x + 2}{x ^{2} - 4}

\frac{x - 1}{x + 2}

Solution steps

\frac{x ^{2} - 3 x + 2}{x ^{2} - 4}

Factor

x^{2} - 3 x + 2 : (x - 1) (x - 2)

= \frac{( x - 1 ) ( x - 2 )}{x ^{2} - 4}

Factor

x^{2} - 4 : (x + 2) (x - 2)

= \frac{( x - 1 ) ( x - 2 )}{( x + 2 ) ( x - 2 )}

Cancel the common factor:

x - 2

= \frac{x - 1}{x + 2}

\frac{3}{8} + \frac{9}{10}

x^{3} - x y + x^{2} - y

9 n + 3 n

(2 x - 3) (2 x + 4)

\frac{- 2}{∣ - 2 ∣}