What is (x+1)^2-(x+1) ?

The solution to (x+1)^2-(x+1) is x^2+x

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simplify (x+1)^2-(x+1)

simplify

(x + 1)^{2} - (x + 1)

x^{2} + x

Solution steps

(x + 1)^{2} - (x + 1)

Apply the distributive law:

- (a + b) = - a - b

- (x + 1) = - x - 1

= (x + 1)^{2} - x - 1

Expand

(x + 1)^{2} : x^{2} + 2 x + 1

= x^{2} + 2 x + 1 - x - 1

Group like terms

= x^{2} + 2 x - x + 1 - 1

Add similar elements:

2 x - x = x

= x^{2} + x + 1 - 1

Subtract the numbers:

1 - 1 = 0

= x^{2} + x

(2 x - 7) - (x + 3)

5 m + 2 (2 m - 7)

(5 ab - 3 x y^{5})^{2}

\frac{5}{- 9}

15 - (- 11)