What is (2^{-1}+4^{-1})/(3^{-1)} ?

The solution to (2^{-1}+4^{-1})/(3^{-1)} is 9/4

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simplify (2^{-1}+4^{-1})/(3^{-1)}

simplify

\frac{2 ^{- 1} + 4 ^{- 1}}{3 ^{- 1}}

\frac{9}{4}

Decimal Notation

2.25

Solution steps

\frac{2 ^{- 1} + 4 ^{- 1}}{3 ^{- 1}}

Simplify

2^{- 1} + 4^{- 1} : \frac{3}{4}

= \frac{\frac{3}{4}}{3 ^{- 1}}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{3}{4 \cdot 3 ^{- 1}}

Simplify

\frac{3}{3 ^{- 1}} : 3^{2}

= \frac{3 ^{2}}{4}

3^{2} = 9

= \frac{9}{4}

- 3 \frac{7}{16}

- 348

- 332

\frac{1}{10} \div \frac{4}{7}

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What is (2^{-1}+4^{-1})/(3^{-1)} ?
The solution to (2^{-1}+4^{-1})/(3^{-1)} is 9/4