What is expand (x+2)(x-4)(x+3) ?

The solution to expand (x+2)(x-4)(x+3) is x^3+x^2-14x-24

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

expand (x+2)(x-4)(x+3)

expand

(x + 2) (x - 4) (x + 3)

x^{3} + x^{2} - 14 x - 24

Solution steps

(x + 2) (x - 4) (x + 3)

Expand

(x + 2) (x - 4) (x + 3) : (x^{2} - 2 x - 8) (x + 3)

= (x^{2} - 2 x - 8) (x + 3)

Distribute parentheses

= x^{2} x + x^{2} \cdot 3 - 2 xx - 2 x \cdot 3 - 8 x - 8 \cdot 3

Simplify

x^{2} x + x^{2} \cdot 3 - 2 xx - 2 x \cdot 3 - 8 x - 8 \cdot 3 : x^{3} + x^{2} - 14 x - 24

= x^{3} + x^{2} - 14 x - 24

\frac{120}{40}

\frac{- 4 x ^{2}}{x}

\frac{12 m ^{2}}{( 4 m ) ^{- 4}}

(2 x^{2} - 18) (x + 3) (x - 3)

(t + 4)^{2} ((t + 4) - 4)

What is expand (x+2)(x-4)(x+3) ?
The solution to expand (x+2)(x-4)(x+3) is x^3+x^2-14x-24