What is factor 25x^2+20xy+4y^2 ?

The solution to factor 25x^2+20xy+4y^2 is (5x+2y)^2

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factor 25x^2+20xy+4y^2

factor

25 x^{2} + 20 x y + 4 y^{2}

(5 x + 2 y)^{2}

Solution steps

25 x^{2} + 20 x y + 4 y^{2}

Rewrite in the form of

a^{2} + 2 ab + b^{2} :

25 x^{2} = (5 x)^{2}

4 y^{2} = (2 y)^{2}

20 x y = 2 \cdot 5 x \cdot 2 y

= (5 x)^{2} + 2 \cdot 5 x \cdot 2 y + (2 y)^{2}

Apply Perfect Square Formula:

a^{2} + 2 ab + b^{2} = (a + b)^{2}

(5 x)^{2} + 2 \cdot 5 x \cdot 2 y + (2 y)^{2} = (5 x + 2 y)^{2}

= (5 x + 2 y)^{2}

- 6 f + 12

63 \cdot 63

\frac{4 + 3 i}{3 + 4 i}

16 + 4 d

- \frac{4}{5} \cdot 10

What is factor 25x^2+20xy+4y^2 ?
The solution to factor 25x^2+20xy+4y^2 is (5x+2y)^2