What is (6x^3-9x^2+18x)/(3x) ?

The solution to (6x^3-9x^2+18x)/(3x) is 2x^2-3x+6

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simplify (6x^3-9x^2+18x)/(3x)

simplify

\frac{6 x ^{3} - 9 x ^{2} + 18 x}{3 x}

2 x^{2} - 3 x + 6

Solution steps

\frac{6 x ^{3} - 9 x ^{2} + 18 x}{3 x}

Factor

6 x^{3} - 9 x^{2} + 18 x : 3 x (2 x^{2} - 3 x + 6)

= \frac{3 x ( 2 x ^{2} - 3 x + 6 )}{3 x}

Cancel the common factor:

3

= \frac{x ( 2 x ^{2} - 3 x + 6 )}{x}

Cancel the common factor:

x

= 2 x^{2} - 3 x + 6

(5^{3} \cdot 2^{- 6})^{- 2}

1.0 4^{8}

500 \cdot 1 0^{- 3}

\frac{2}{x + 6}

(7 + 5)^{2}

What is (6x^3-9x^2+18x)/(3x) ?
The solution to (6x^3-9x^2+18x)/(3x) is 2x^2-3x+6