What are the solutions to the equation -12x^2+21=0 ?

The solutions to the equation -12x^2+21=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

Find the zeros of -12x^2+21=0

The zeros of -12x^2+21=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2

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- 12 x^{2} + 21 = 0

x = \frac{7}{2}, x = - \frac{7}{2}

Decimal Notation

x = 1.32287 \dots, x = - 1.32287 \dots

Solution steps

- 12 x^{2} + 21 = 0

Move

21

to the right side

- 12 x^{2} = - 21

Divide both sides by

- 12

x^{2} = \frac{7}{4}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{7}{4}, x = - \frac{7}{4}

\frac{7}{4} = \frac{7}{2}

- \frac{7}{4} = - \frac{7}{2}

x = \frac{7}{2}, x = - \frac{7}{2}

(x - 6) (x + 4) > 0

9 x = - 63

\frac{1}{5} x + \frac{1}{3} x = 2

∣ x - 22 ∣ \leq 6

72 \cdot 2

What are the solutions to the equation -12x^2+21=0 ?
The solutions to the equation -12x^2+21=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2
Find the zeros of -12x^2+21=0
The zeros of -12x^2+21=0 are x=(sqrt(7))/2 ,x=-(sqrt(7))/2